MODEL

Physical situation

Bodies
Custom modelling switches

This is a custom teaching switch: it removes the selected weight force while retaining the entered mass in F = ma. In 9MA0, the word light is normally used for strings, rods or pulleys whose mass is neglected—not for a massive particle.

Gravity

9MA0 normally uses 9.8 m s⁻² unless a question specifies another value.

Geometry
Lift motion

Positive means upward; negative means downward. The model treats this acceleration as given and calculates the contact reaction and cable tension required.

Ladder geometry

The ladder is modelled as uniform, so its own weight acts at the midpoint. The person is modelled as a particle at the selected distance along the ladder.

Wall friction

This preset models the wall contact at limiting equilibrium, so the upward wall friction is FW = μWRW. The model then checks whether the floor can provide the required friction.

String geometry

Angles are measured above the horizontal. Both strings are light and taut.

Rod and string geometry
Rod and peg geometry

The rod is horizontal, uniform and hinged at A. A smooth peg supports it from below; the hanging mass is attached at the far end by a light string.

Rod directions

Positive solved member force means tension; a negative value is automatically interpreted as compression.

2D force inputs

F₁ and F₃ are entered in magnitude–direction form. F₂ is entered directly using the selected vector notation as i and j components.

Specified resistance

D is a stated resistive force, not friction. It acts opposite the indicated motion and is not calculated using μR.

Second inclined plane

Both planes are smooth in this template. Positive motion is A up its slope and B down its slope.

Rod + peg geometry

The foot is on rough horizontal ground. The peg/cylinder is smooth, so its reaction is perpendicular to the rod.

Horizontal plank geometry

The plank is uniform and horizontal. The string is attached at the far end; the particle is modelled as resting on the plank.

Applied force ?

Use the usual maths angle convention: 0° = right, 90° = up, 180° = left, −90° = down. “Push” and “Pull” do not change the force vector itself; they change which side of the body the source icon appears on in the physical scene.

Surface
String & pulley

The connected-particle presets use a light, inextensible string and a smooth, light pulley. Unticking “taut” removes the tension and linked-acceleration constraint.

Extra forces

Each extra force has a clear label, magnitude, angle and action type. On two-body models, you can also choose whether it acts on A or B. The physical scene uses a compact pusher pad for a push and a short cable/handle for a pull. These show the external agent and line of action without turning the situation picture into a force diagram.

START HERE

How to use Mechanics Lab

This site is designed to make the modelling decisions in 9MA0 visible. Start with a physical situation, decide what forces belong in the model, then turn the force diagram into mathematics.

Quick start Three modes Reading the diagrams Worked examples Using it for exam practice
THE ROUTE THROUGH THE SITE

A six-step routine

You do not need to use every control. A useful first visit follows this sequence.

1

Choose a situation

Use the home screen to choose the physical setup you want to model. The top-left ΣF icon always brings you back here.

2

Choose a mode

Select Explore, Build, or Practice. The same mechanics engine is underneath all three; the amount of support changes.

3

Read the physical picture

Look at the objects, geometry, contacts and motion information first. The physical picture deliberately does not contain force arrows.

4

Model the forces

Focus on one body at a time. Predict the forces, reveal the free-body diagram, and click a force to see why it acts and where its partner acts.

5

Build the mathematics

Choose useful axes, resolve only when needed, then move through the Mathematics steps from modelling to a checked result.

6

Interpret

Explain what the answer means physically. Change one variable and predict what should change before you move it.

Situation→Assumptions→FBD→Axes / components→Mathematics→Interpret
STEP 2

Choose how you want to work

You choose a mode immediately after choosing a situation. You can switch mode later from the top of the page.

Explore

Change things and notice patterns

The modelling layers are available immediately. Change one variable at a time, predict what will happen, then inspect the force diagrams and Mathematics workspace.

Useful when: meeting an idea for the first time, demonstrating at the front of class, or investigating a limiting case.
Build

Predict before the site reveals

Start from the physical picture and choose which types of force you expect. Reveal the generated FBD only after committing to a prediction.

Useful when: learning to construct free-body diagrams and deciding which interactions matter.
Practice

Treat the screen like an exam question

Read the question and physical model, then work on paper. Reveal the correct diagrams or full solution only when you want feedback.

Useful when: revising, checking independent modelling, or practising exam technique.
READING THE SITE

What each diagram is telling you

The site separates the real situation from the mathematical representations built from it.

Physical situation

This shows objects, strings, surfaces, hinges, geometry and motion information. It does not show force arrows. Ask: what is touching or pulling what?

Free-body diagram

This shows only the forces acting on the selected body. Weight acts through the centre of mass; contact forces act at contacts; tension acts along a string.

Resolving forces

When you choose components, the original oblique force is replaced by its components. You never see the original force and its components as if they were three separate forces.

Symbols and numerical values

Keep the FBD clean with Symbols only. Use On hover / tap to inspect one value, or Value key below to see the current values without lengthening every arrow label.

Individual body vs system

A system diagram appears only when grouping bodies is useful. Internal forces such as contact or tension can disappear from a whole-system equation because the interaction is inside the chosen boundary.

Linked forces

Click a force arrow to see its explanation. Newton III partners are linked across diagrams. Equal tensions in an ideal string are shown as a constraint, not incorrectly labelled as a Newton III pair.

Geometry angles

Essential shows the angles needed immediately. More detail reveals useful equal, complementary or perpendicular angles when the geometry is part of the modelling.

Model assumptions

The assumption chips tell you what the mathematical model is ignoring or idealising. Open the explanation and ask which conclusion depends on each assumption.

EXAMPLES

Three ways to use the journey

These examples show the thinking the site is trying to develop, not just which buttons to press.

Example 1: rough inclined plane

Goal: understand friction and resolving weight.

  1. Choose Particle on a rough slope and Build.
  2. Before revealing anything, predict weight, reaction and friction.
  3. Reveal the FBD and decide which way friction should act.
  4. Use Show components. Notice that mg is replaced by mg sin θ and mg cos θ.
  5. Change μ or θ and find the boundary between equilibrium and motion.

Example 2: two particles and a pulley

Goal: connect two FBDs without confusing equal tension with Newton III.

  1. Choose Table mass + hanging mass.
  2. Draw separate FBDs for A and B on paper.
  3. Reveal one body at a time, then compare the diagrams.
  4. Inspect the tension arrows. Their equality comes from the ideal-string model.
  5. Open the coupled-system view and notice which internal forces disappear.

Example 3: ladder and moments

Goal: see why force positions and pivot choice matter.

  1. Choose Ladder against a smooth wall and Explore.
  2. Identify where the ladder weight, person weight and contact forces act.
  3. Ask which pivot removes the most unknown forces.
  4. Move the person up the ladder and predict how the wall reaction changes.
  5. Use the equations only after explaining the moment change in words.
PRACTICE MODE

Use the site without letting it do the thinking for you

The most useful exam routine is to delay the reveal until you have committed something to paper.

Before revealing support

  • Sketch the physical situation if needed.
  • Draw the FBD for the body or system you choose.
  • State the modelling assumptions you are using.
  • Choose positive directions or a sensible moment centre.
  • Write the equations you think will be needed.

After revealing support

  • Compare force types, directions and application points, not only numerical answers.
  • If your diagram differs, click the force to understand the interaction.
  • Use Framework or Terms before jumping to Solve.
  • Change one variable and check whether your explanation still makes sense.
  • Return Home with the ΣF icon when you want a new situation.
Remember: the aim is not to copy the generated diagram. The aim is to become able to build the same model independently from an unfamiliar mechanics question.
9MA0 MECHANICS GUIDE

Forces, Newton's laws and modelling assumptions

A quick-reference guide for deciding what belongs on a mechanics model, where forces act, and what common modelling words actually change.

Forces Newton's laws Modelling assumptions Worked examples Common traps
FORCES

What forces can appear?

Ask what is interacting with the body. Every force should have a physical reason.

↓

Weight, mg

Cause: gravitational interaction with Earth.

Direction: vertically downward.

Where: centre of mass; for a uniform rod, the midpoint.

Not “down the slope”. Weight is vertical even when the surface is inclined.
⊥

Normal reaction, R

Cause: contact between surfaces.

Direction: perpendicular to the contact surface.

Where: at the contact.

Do not assume R=mg. On a rough contact, this is only the normal component of the total contact reaction.
↗

Total contact reaction, C

At a rough contact: the surface may exert both normal reaction R and friction F.

Resultant: these can be represented by one total contact reaction.

Magnitude: C=√(R²+F²) when the components are perpendicular.

The website can optionally draw this as a dashed derived resultant. It is not an extra force in addition to R and F.
⇆

Friction, F

Cause: rough contact.

Direction: opposes relative motion or the tendency to slide.

Where: along the contact surface.

Use F=μR only when sliding or in limiting equilibrium. Otherwise F≤μR.
↔

Tension, T

Cause: a taut string or cable pulling on a body.

Direction: along the string, away from the body.

Where: at the attachment point.

A string can pull but cannot push. A slack string has zero tension.
→←

Thrust / compression

Cause: a rod or member pushing on a joint/body.

Direction: along the member.

Where: at the joint or attachment.

A light two-force member may be in tension or compression; the solved sign tells you which.
↗

Applied force, P

Cause: an external push or pull.

Direction: as specified in the problem.

Where: at the stated application point.

An angled applied force may change the normal reaction and therefore the friction.
←

Resistance / drag

Cause: the surrounding medium or a stated resistance to motion.

Direction: opposite the motion relative to the medium.

Where: usually represented as a single force in a particle model.

Do not invent air resistance when the model says it is negligible. If a resistance is given, include exactly what the question states.
●

Hinge / support reaction

Cause: a pin, hinge, support or axle constraining the body.

Direction: not always known in advance; often resolve into horizontal and vertical components.

Where: at the hinge/support.

An ideal pin hinge supplies a force but no couple. Taking moments about it removes its unknown reaction from the moment equation.
NEWTON'S LAWS

What does the resultant force tell us?

Mechanics questions often test the decision about which law applies before they test the algebra.

Newton I — zero resultant

If the resultant force on a particle is zero, its acceleration is zero. It may be stationary or moving with constant velocity.

ΣF = 0 ⇒ a = 0

A common mistake is to conclude that zero resultant means the object must be at rest.

Newton II — non-zero resultant

The vector resultant determines the acceleration. Resolve in useful directions or use vector notation.

ΣF = ma

The acceleration points in the direction of the resultant force, not necessarily the direction of the velocity.

Newton III — interactions come in pairs

Two interacting bodies exert equal-magnitude, opposite-direction forces on each other. The pair acts on different bodies.

FA on B = −FB on A

Equal tensions on two particles are not automatically a Newton III pair.

MODELLING LANGUAGE

What do the assumptions mean?

These words are instructions about what to include or ignore. For each one, ask: what complexity does this remove, and what equation or force relationship does it justify?

Particle

Size, shape and rotation are ignored. Forces can be represented through one point when only translation matters.

Rigid body / rigid rod

The object does not deform. Force positions matter, so moments can be taken about points.

Uniform rod / ladder

Mass is evenly distributed, so its centre of mass is at the midpoint.

Light string / rod / pulley

Its own mass is neglected, simplifying the force model. In 9MA0, “light” is normally used for connectors/supporting components such as strings, rods or pulleys—not as a synonym for “ignore the weight of a massive particle”.

Inextensible string

The total string length is fixed. Connected particles have linked displacement, velocity and acceleration magnitudes while the string is taut.

Taut string

The string remains straight and can transmit tension. If it becomes slack, tension becomes zero and the motion constraint disappears.

Smooth surface

No friction acts at that contact. A normal reaction may still act.

Rough surface

Friction may act. Its magnitude depends on whether the contact is static, limiting or sliding.

Smooth pulley

The pulley does not introduce a frictional difference in tension between the two sides of the same ideal string.

Smooth peg / smooth contact

No friction acts at the contact. The contact reaction acts normal to the touching surfaces; for a rod resting on a smooth peg, this is perpendicular to the rod.

Limiting equilibrium

The body is on the point of slipping, so the friction has reached its maximum value: F=μR.

Negligible air resistance

No drag force is included. This is common unless resistance is explicitly given.

Constant gravity

Use one fixed gravitational field strength throughout the model. 9MA0 normally uses g=9.8 m s⁻², but a question may specify another value such as 10 m s⁻²; the lab's Advanced settings allow this to be changed.

EXAMPLES

From situation to model

Each example follows the same question: “What is interacting with the body?”

1

Block on a rough slope

A
  1. Earth gives weight mg, vertically down.
  2. The slope gives a normal reaction perpendicular to itself.
  3. Because the contact is rough, friction may act along the slope.
  4. Choose axes along/perpendicular to the slope before resolving weight.
Perpendicular equilibrium: R − mg cos θ = 0
2

Two particles and a pulley

AB
  1. Draw a separate FBD for each particle.
  2. Each has its own weight.
  3. A taut light string supplies tension along the string.
  4. If both particles are grouped, the string tension is internal and cancels from the combined path equation.
Constraint: |a_A|=|a_B|
3

Uniform ladder against a wall

  1. The ladder weight acts at its midpoint.
  2. Each contact can supply a normal reaction.
  3. A rough contact may also supply friction.
  4. Force positions matter, so use moments as well as force balance.
Useful choice: take moments about the foot to eliminate both floor forces.
CHECK YOUR MODEL

Common mechanics traps

Components are not new forces.

mg sin θ and mg cos θ are components of the one weight force.

Equal tensions are not automatically a Newton III pair.

They can be equal because of the light-string/smooth-pulley model.

Friction is not always μR.

Static friction takes the value needed up to its maximum.

Acceleration and velocity are different.

A body can be moving one way while accelerating the other way.

Internal forces depend on your chosen system.

Tension/contact can disappear from a whole-system equation when both interacting bodies are included.

Moments need real lines of action.

Do not move support forces to the centre of a rigid body just to make the picture simpler.

Zero resultant does not mean zero velocity.

Newton I says zero resultant gives zero acceleration; a body may still move with constant velocity.

Normal reaction is not always the whole contact reaction.

At a rough contact, normal reaction and friction are perpendicular components of the resultant contact force.

Diagram
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